Unknown gas ocupies 322ml at 29 and 616 m how many molecules are there in this gas
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Answer:
6.3231 × 10^21 molecules
Explanation:
If the unknown gas is ideal then,
P = 616 mm of Hg = 0.810526 atm
T = 29°C = 302 K
R = 0.0821 atm L / (mol K)
n = PV / (RT)
= (0.810526 atm × 322 × 10^-3 L) / (0.0821 atm L / (mol K) × 302)
= 10.5 × 10^-3 mol
Number of molecules present in given gas
= 10.5 × 10^-3 mol × 6.022 × 10^23 molecules/mol
= 6.3231 × 10^21 molecules
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