Unknown resistance X is joined parallel to a resistance of 20 Ω. To this combination a battery of 2 V and resistance of 10 Ω are joined in series. If the current passing through X is 0.05 A. Find the value of X.
Answers
Answer:
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Explanation:
The total resistance of a circuit connected to the given cell of emf 15 V is the sum of all the resistances from various sources like, resistors, ammeter, voltmeter, etc., connected in series along with the internal resistance of the cell.
In this case, the total resistance is given as 3Ω+3Ω+6Ω=12ohms.
From the ohm's law the total current can be calculated from the formula I=V/R.
That is, I=
R
V
=
12A
15V
=1.25A.
Hence, the current through the battery is 1.25 amperes.
The voltage output of a device is measured across its terminals and is called its terminal voltage V. Terminal voltage is given by the equation V=emf−Ir where, r is the internal resistance and I is the current flowing at the time of the measurement.
Therefore, V=15V−(1.25×3)=11.25V.
Hence, the potential difference across the terminals of the cell is 11.25V
Answer:
Frankly the unknown resistance X has a value of 16.67 Ω when joined in parallel with a resistance of 20 Ω and connected in series with a battery of 2 V and resistance of 10 Ω, and the current passing through X is 0.05 A.
Explanation:
Let's use Ohm's law to find the equivalent resistance of the parallel combination of X and 20 Ω resistors:
1/Req = 1/X + 1/20
Req = (X*20)/(X+20)
Now, we can use Kirchhoff's voltage law (KVL) to find the current passing through the circuit:
2 - Ieq*(Req + 10) = 0
Ieq = 2/(Req + 10)
Moreover we know that the current passing through X is 0.05 A, so we can write:
0.05 = Ieq * X
Substituting Ieq with 2/(Req + 10), we get:
0.05 = 2X / (X20/(X+20) + 10)
Solving for X, we get:
X = 16.67 Ω
Therefore, the value of X is 16.67 Ω.
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Learn more about Ohm's law: https://brainly.in/question/6604237
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