Physics, asked by itzmetanbir, 3 months ago

unpolarized light intensity I0 in incident on an ideal linear polarizer(no absorption). what is the transmitted intensity?​

Answers

Answered by Naina323
3

Answer:

When unpolarized light passes through a polarizer, the intensity is reduced by a factor of ½. The transmitted light is polarized along the axis of the polarizer.

Answered by 3rdlaw
0

Answer:

Explanation:

When unpolarized light passes through an ideal linear polarizer, the transmitted light becomes polarized, with the electric field vector oriented in a single direction perpendicular to the transmission axis of the polarizer.

The transmitted intensity is then given by the

Malus' law:I = I0 * cos^2(theta)

where I0 is the intensity of the incident unpolarized light, and theta is the angle between the polarization direction of the incident light and the transmission axis of the polarizer.

Since the incident light is unpolarized, the average value of theta is 45 degrees, and the transmitted intensity is:

I = I0 * cos^2(45) = I0 * 1/2

So the transmitted intensity is half the intensity of the incident light.

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