Unpolarized light of intensity 25.8 W/cm2 is incident on two polarizing filters. The axis of the first filter is at an angle of 25.6 ∘ counterclockwise from the vertical (viewed in the direction the light is traveling) and the axis of the second filter is at 57.0 ∘ counterclockwise from the vertical. What is the intensity of the light after it has passed through the second polarizer?
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The intensity of second light through the second polarizer is Io = 9.359 W/cm^2
Explanation:
We are given that:
- Intensity of light = 25.8 W/cm^2
- Angle θ1 = 25.6∘
- Axis of 2nd filter θ2 = 57.0∘
I1 = Io / 2
I1 = 0.5 Io
I2 = Io cos^2 (57° - 25.6°)
Now solve these equations:
I2 = 0.5 Io cos^2 (31.4°)
Io = 0.5 Io (0.85)^2
Io = 0.5 x 25.8 x 0.7225
Io = 9.359 W/cm^2
Thus the intensity of second light through the second polarizer is Io = 9.359 W/cm^2
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