Math, asked by gyaneshsahoo2810, 10 months ago

Uparyukt sarvsamika ke upyog se, (104)³ ka maan gyat kijiye?

Answers

Answered by devrajdeora1998
1

Answer:

104³ = 1124864

Step-by-step explanation:

104³ = (100+4)³

since (a+b)³ = a³+b³+3ab(a+b)

a = 100 and b = 4

=> 100³ + 4³ + 3×100×4(100+4)

=> 1000000 + 64 + 1200(104)

=> 1000064 + 124800

=>1124864

Answered by deepakdhiman0143
0

Step-by-step explanation:

(104)³ 

=(100 + 4)³ 

use ( a +b)³ = a³ + b³ + 3ab( a + b)

then,

( 100 + 4)³ = ( 100)³ +(4)³ +3(100)(4)(100+4)

=(10²)³ + 64 + 1200(104)

=1000000 + 64 + 124800

=1124864 (answer )✔

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