Question

UPMT 081
motion of a particle executing SHM in one
direction
is described by
x=-0.5 sin(2t + rt/4)where x is in
metres and t in seconds. The frequency of

oscillation in Hz is

​

Answer 1

Answer:

1/π

Explanation:

Comparing to equation:

x= Asin(wt+¢)

We get,

w= 2

or, 2πn=2. (w=2πn)

so, n= 1/π hz

hope this is your answer