Math, asked by ankitabhide, 1 year ago

upper limit π\2 and lower limit 0 sin²x dx will be:​

Answers

Answered by aribadesigns73
1

Answer:

=1

Step-by-step explanation:

=sin^2(π\2)-sin^(0) as sinπ\2=1 and sin(0)=0

=(1)^2-(0)^2

=1-0

=1

Similar questions