Math, asked by chaganrahangdale12, 17 days ago

uppose you are given a circle. Give a construction to find its centre
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Answers

Answered by Equuleus
0

To find the centre of a circle:

Step 1: Mark any 3 points on the circle as A B C

Step 2: Join chords AB and BC

Step 3: Construct the perpendicular bisectors of chords AB and BC

Step 4: Mark the point where these two bisectors intersect as O

O is the centre of the circle.

I hope this helped!

Answered by rudravashisth
0

Answer:

Let circle C

1

be given.

We have to find its centre.

1) Take points P, Q, R on the circle.

2) Join PR and RQ.

We know that perpendicular bisector of a chord passes through the centre. So, we construct perpendicular bisectors of PR & RQ .

3) Take a compass. With point P as pointly end and R as pencil end of the compass, mark an arc above and below PR .

Do same with R as pointly end and P as pencil end of the compass.

4) Join the points intersected by the arcs.

The line joined is the perpendicular bisector of PR.

5) Take a compass. With point R as pointly end and Q as pencil end of the compass, mark an arc above and below RQ.

Do same with Q as pointly end and R as pencil end of the compass.

6) Join the points intersected by the arcs. The line joined is the perpendicular bisector of RQ.

7) The point where the two perpendicular bisectors intersect is the centre of the circle.

8) Mark it as point O.

Thus, O is the centre of the given circle.

solution

Step-by-step explanation:

I HOPE IT WILL HELP YOU

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