Question

Upto how much height a ball
will reach, which is thrown
vertically above with
a initial velouty of 30m/s(10m/s^2)​

Answer 1

Answer:

sorry moti search form online please

Answer 2

Answer:

45 m

Explanation:

here we applied formula v=u+at  for finding time

here v=0

u=30m/s

Acceleration= 10m/s or 9.8m/s

t=?

so

0=30+(-10t)

-10t=-30

t=30/10

for s,

s = ut + at²/2

s = 90 - 45

s = 45 m