Question

(UR)
B)Agirl stands on the building of 60mt height and observe bottoms of
two trees which are either side of building at the angles of
depression.
45° and 30° Find the distance between 2 trees.​

Answer 1

Distance between the two trees = (120 + 60√2) m

Let the angle of depression of one tree be 45° and the tree be 30° from the top the building.

Let the distance of the tree with 45°

angle of depression from the building be x and that of the tree with 30° depression be y.

Height of the building = h = 60 m

For ∆ ADB as shown in the figure -

sin45° = h/x

=> 1/√2 = 60/x

=> x = 60√2 m

For ∆ ADC as shown in the figure -

sin30° = h/x

=> 1/2 = 60/x

=> y = 120 m

Distance between the two trees = x + y = (120 + 60√2) m