Physics, asked by sara1626, 11 months ago

uranium 238 decay by an alpha particle to form Thorium. complete the nuclide equation for the this decay​


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Answered by Anonymous
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Uranium-238 produces thorium-234 by alpha decay.

An α-particle is a helium nucleus. It contains 2 protons and 2 neutrons, for a mass number of 4.

During α-decay, an atomic nucleus emits an alpha particle. It transforms (or decays) into an atom with an atomic number 2 less and a mass number 4 less.

Thus, uranium-238 decays through α-particle emission to form thorium-234 according to the equation:

238

92

U

l

234

90

Th

+

4

2

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