Urea is a very important nitrogenous fertilizer.Its formuale is CON2H4. Calculate the percentage of carbon in urea.
(C = 12, O = 16, N =14, H = 1)
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Answered by
2
Answer:
20% is the correct answer
Explanation:
12/60*100=20%
Answered by
2
Answer:
20%
Explanation:
we know
mass percentage of carbon in urea = molar mass of carbon / molar mass of urea × 100
Thus, the molar mass of urea = 12+16+2×14+4×1 = 60
( the molecular formula of carbon in urea is CON2H4 )
Mass percentage of carbon in urea = 12/60×100
= 20%
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