Question

Urea is a very important nitrogenous fertilizer.Its formuale is CON2H4. Calculate the percentage of carbon in urea.
(C = 12, O = 16, N =14, H = 1)


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Answer 1

Answer:

20% is the correct answer

Explanation:

12/60*100=20%

Answer 2

Answer:

20%

Explanation:

we know

mass percentage of carbon in urea = molar mass of carbon / molar mass of urea × 100

Thus, the molar mass of urea = 12+16+2×14+4×1 = 60

( the molecular formula of carbon in urea is CON2H4 )

Mass percentage of carbon in urea = 12/60×100

= 20%