Question

Urea on hydrolysis produces ammonia
and carbon dioxide. The standard
entropies of urea, H,O, CO, NH, are
173.8, 70, 213.5 and 192.5) mole 'K
respectively. Calculate the entropy
change for this reaction.​

Answer 1

Answer:

S°(urea) = 173.8 J mol-1 K-1 S° (H2O) = 70 J mol-1K-1 S° (CO2) = 213.5 J mol-1 K-1 S° (NH3) = 192.5 J mol-1 K-1 NH2 – CO – NH2 + H2O → 2NH3 + CO2 ∆Sr° = ∑(S°)product – ∑(S°)reactants ∆Sr° = [2 S°(NH3) + S°(CO2)] — [S°(urea) + S°(H2O)] ∆Sr° = [2 x 192.5 + 213.5] – [173.8 + 70] ∆Sr° = [598.5] – [243.8] ∆Sr° = 354.7 J mol-1 K-1Read more on Sarthaks.com - https://www.sarthaks.com/931999/urea-hydrolysis-produces-ammonia-and-carbon-dioxide-the-standard-entropies-urea-h2o-co2

Explanation:

Urea on hydrolysis produces ammonia and carbon dioxide. The standard entropies of urea, H2O. CO2, NH3 are 173.8, 70, 213.5 and 192.5 J mole-1K-1 respectively. Calculate the entropy change for this relation.Read more on Sarthaks.com - https://www.sarthaks.com/931999/urea-hydrolysis-produces-ammonia-and-carbon-dioxide-the-standard-entropies-urea-h2o-co2