Question

URGENT


A truck accelerates uniformly from rest to a speed of 9.2m/s over a distance of 26.2m . Determine the acceleration of the Truck



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Answer 1

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Answer 2

Answer:

$\bigstar{\bold{Acceleration=1.62\:m/s^{2} }}$

Step-by-step explanation:

$\Large{\underline{\underline{\bf{Given:}}}}$

• Initial speed of truck = 0 m/s
• Final speed of truck = 9.2 m/s

$\Large{\underline{\underline{\bf{To\:Find:}}}}$

• The acceleration of the truck

$\Large{\underline{\underline{\bf{Solution:}}}}$

→ Here we have to find the acceleration of the truck.

→ By the third equation of motion we know that,

 v² - u² = 2as

  where v = final velocity

  u = initial velocity

  a = acceleration

  s = distance covered

→ Substitute the data,

  9.2² - 0² = 2 × a × 26.2

  9.2² = 52.4 a

  84.64 = 52.4 a

  a = 84.64/52.4

  a = 1.62 m/s²

→ Hence the acceleration of the truck is 1.62 m/s²

$\boxed{\bold{Acceleration=1.62\:m/s^{2} }}$

$\Large{\underline{\underline{\bf{Notes:}}}}$

→ The three equations of motion are:

• v = u + at
• s = ut + 1/2 × a × t²
• v² - u² = 2as

→ where v = final velocity

              u = initial velocity

              t = time taken

              a = acceleration

              s = distance