URGENT!!! Answer all questions.Read before you answer.Subject~~Mathematics
1)Answer must include steps
2)People who know all answers must only answer.
3)If you don't know any of answers pls don't answer and waste my time your time and my points.. I will report such incomplete answers
4)Write answers in a paper and send the photo of it
5) I will reward 20 Points
Thnx..
Attachments:
Answers
Answered by
1
(19) Given,
(21) 8 periods => 45 mins10 periods =?8×45 =10 × x8×45 /10 =xx=36minsAnswer : 36mins
(22) If the number of animals increases food will last lesser number of days.Thus two quantities vary inverselyAnimals to feed =>20302030Number of days food last =>6x6xx=4x=4Thus the food will last for 4 daysAnswer : 4 days
Hope all r correct!!
cheers!!
Dimensions of cuboid : 40mx30mx20m,
volume of cuboid = 40∗30∗2040∗30∗20 = 24,000m324,000m3
Also, volume of one small cube : 0.6m0.6m. Its volume = 0.6∗0.6∗0.6=0.216m30.6∗0.6∗0.6=0.216m3
Thus, number of cubes which would fit insde the cuboid are : 240000.216=111111.112≈1,11,111240000.216=111111.112≈1,11,111
(taking the lower number because it would just be the cubes that would fit in.)
(21) 8 periods => 45 mins10 periods =?8×45 =10 × x8×45 /10 =xx=36minsAnswer : 36mins
(22) If the number of animals increases food will last lesser number of days.Thus two quantities vary inverselyAnimals to feed =>20302030Number of days food last =>6x6xx=4x=4Thus the food will last for 4 daysAnswer : 4 days
Hope all r correct!!
cheers!!
Attachments:
Steph0303:
i didnt do last 3 sums which werenot clear to me therefore pls mark me the brainliest atleast thx
it's okay you answered all my difficult questions bro
where is answer 20????
the last img in which i have writtenis the 20 th one
Similar questions