Math, asked by dsharma5902p3xbhp, 11 months ago

urgent answer please​

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Answered by presto
1

Answer:

=>cos^-1{1/√2 cos 9pi/10 - 1/√2 sin 9pi/10}

=>cos^-1{cos pi/4 cos 9pi/10- 1/√2 sin 9pi/10}

=>cos^-1{cos(pi/4+9pi/10)} ----------->cos(A+B)= cosA cosB - sinA sinB

=>cos^-1{cos(23pi/20)}

=>cos^-1{cos(pi+3pi/20)}

=>cos^-1{-cos(3pi/20)}

=>pi- cos^-1{cos(3pi/20)} --------------->cos^-1(-x) = pi- cos^-1(x)

=>pi-3pi/20= 17pi/20

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