Question

Urgent answer please

Answer 1

Bonjour!!

${3}^{x - 1} = 9 \\ \\ {3}^{3 - 1} = 9 \\ \\ so... \: x = 3$
$\\ \\ {4}^{y + 2} = 64 \\ \\ {4}^{1 + 3} = 64 \\ \\ so..y = 1$
$to \: find : \\ \frac{y}{ x} - \frac{x}{y} \\ \\ sol : \\ \\ we \: have : x = 3 \: \: y = 1 \\ \\ \frac{1}{3} - \frac{3}{1} \\ \\ \frac{1 - 9}{3} = - \frac{8}{3}$

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