Math, asked by arpita415, 1 year ago

urgent answer plz now

Attachments:

Answers

Answered by Anonymous
0
soo here ur answer
Let three angles of the triangle are A, B and C

Let C= 130   (One angel is given as 130)

Then A+B = 180-130 = 50  (since A+B+C = 180)

Now 

      C + A/2 + B/2 = 180   (A/2 and B/2 are the bisector)

=> C + (A+B)/2 = 180

=> C + 50/2 = 180

=> C + 25 = 180

=> C = 180-25

=> C = 155

So the angle between the bisector of the other two angels is 155 degree. 

<marquee>
hope this will help u
#neymarjr3

arpita415: is thinking right
arpita415: is this right
Answered by siddhartharao77
1

Let the angles be x,y,z.

We know that sum of angles of a triangle is 180°.

Given that one of the angles of a triangle is 130.

⇒ ∠x + ∠y + ∠z = 180°

⇒ 130 + ∠y + ∠z = 180

⇒ ∠y + ∠z = 180 - 130

⇒ ∠y + ∠z = 50°.


Now,

The angle formed by the bisectors:

⇒ x + (1/2) ∠y + (1/2) ∠z = 180°

⇒ x + 1/2(∠y + ∠z) = 180°

⇒ x + 1/2(50°) = 180°

⇒ x + 25 = 180

⇒ x = 180 - 25

⇒ x = 155°.


Therefore, angle between the bisectors = 155°.


Hope it helps!

Similar questions