urgent answer plz now
Attachments:
![](https://hi-static.z-dn.net/files/df6/890f82e14f4a26d308399c807d8b17bb.jpg)
Answers
Answered by
0
soo here ur answer
Let three angles of the triangle are A, B and C
Let C= 130 (One angel is given as 130)
Then A+B = 180-130 = 50 (since A+B+C = 180)
Now
C + A/2 + B/2 = 180 (A/2 and B/2 are the bisector)
=> C + (A+B)/2 = 180
=> C + 50/2 = 180
=> C + 25 = 180
=> C = 180-25
=> C = 155
So the angle between the bisector of the other two angels is 155 degree.
![<marquee> <marquee>](https://tex.z-dn.net/?f=%26lt%3Bmarquee%26gt%3B)
hope this will help u
#neymarjr3
Let three angles of the triangle are A, B and C
Let C= 130 (One angel is given as 130)
Then A+B = 180-130 = 50 (since A+B+C = 180)
Now
C + A/2 + B/2 = 180 (A/2 and B/2 are the bisector)
=> C + (A+B)/2 = 180
=> C + 50/2 = 180
=> C + 25 = 180
=> C = 180-25
=> C = 155
So the angle between the bisector of the other two angels is 155 degree.
hope this will help u
#neymarjr3
arpita415:
is thinking right
Answered by
1
Let the angles be x,y,z.
We know that sum of angles of a triangle is 180°.
Given that one of the angles of a triangle is 130.
⇒ ∠x + ∠y + ∠z = 180°
⇒ 130 + ∠y + ∠z = 180
⇒ ∠y + ∠z = 180 - 130
⇒ ∠y + ∠z = 50°.
Now,
The angle formed by the bisectors:
⇒ x + (1/2) ∠y + (1/2) ∠z = 180°
⇒ x + 1/2(∠y + ∠z) = 180°
⇒ x + 1/2(50°) = 180°
⇒ x + 25 = 180
⇒ x = 180 - 25
⇒ x = 155°.
Therefore, angle between the bisectors = 155°.
Hope it helps!
Similar questions