Question

urgent answer plz now

Answer 1

Given :- angle P = 100° , PM bisects angle P , PM perpendicular to QR.

To find :- angle Q.

Solution :- If PM perpendicular to QR, angle PMQ = 90° and angle PMR = 90° and PM bisects angle P, 100/2 = 50°.

In triangle PQM
angle QPM = 50°
angle PMQ = 90°

angle QPM + angle PMQ + angle MQP = 180° (Angle sum property of a triangle)

50° + 90° + angle Q = 180°
140° + angle Q = 180°
angle Q = 180° - 140°
angle Q = 40°

HOPE IT HELPS YOU...

Answer 2

Angle Q will be 40°

Because, In triangle pqr two triangles pqm and PRM are formed by perpendicular PM.

Then, angle Q PM = angle RPM= 50° each because, angle P is bisected by PM.

Also, by angle sum property of a triangle,

In triangle PQM,

Angle QPM + Angle PMQ + Angle PQM = 180°.

Therefore, 50°+ 90°+Angle PQM or Angle Q=180°

140°+ Q= 180°

Or Angle Q= 180-140

Angle Q= 40°

ANS....

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