urgent!!!!!!!!!!! find the complete set of values of a for which the quadratic
x^2 -ax +2=0 has equal roots. pls give correct answer
Answers
Answered by
9
Here,
a = 1
b = -a
c = 2
Discriminant = b² - 4ac
=> (-a)² - 4(1)(2)
=> a² - 8
We know, for equal roots, discriminant = 0
=> a² - 8 =0
=> a² = 8
=> a = 2√2
a = 1
b = -a
c = 2
Discriminant = b² - 4ac
=> (-a)² - 4(1)(2)
=> a² - 8
We know, for equal roots, discriminant = 0
=> a² - 8 =0
=> a² = 8
=> a = 2√2
Anonymous:
but answer is 2+√12 2-√12
we have to find the value of a
So, it is correct
I think... Your question is incomplete
x^2 - ax + a +2 is question
sorry for asking wrongly
anyways, ask again
(-:
Answered by
2
Hey friend your answer is here
Please mark as brainliest
Please mark as brainliest
Attachments:
Similar questions