CBSE BOARD XII, asked by greedy93, 11 months ago

urgent!!!!!!!!

Find the Following:

Sin75°
sin74°
sin15°
sin7°
cos75°​

Answers

Answered by sahildhande987
6

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Attachments:
Answered by Anonymous
0

1)Sin75=sin(30+45)

=Sin30.cos45+sin45.cos30

=1/2.1/√2+1/√2.√3/2

=(1+√3)/2√2

=(√2+√6)/4

2)sin74° = 0.96126

sin 74° = 0.96126

sin 74 degrees = 0.96126

The sin of 74 degrees is 0.96126, the same as sin of 74 degrees in radians.

3)sin15=sin(45–30).

=sin45.cos30-cos45.sin30.

=(1/2^1/2).(3^1/2)/2- (1/2^1/2) .(1/2).

=(3^1/2 - 1)/(2)^3/2

4)sin7° = 0.12187

sin 7° = 0.12187

sin 7 degrees = 0.12187

The sin of 7 degrees is 0.12187, the same as sin of 7 degrees in radians.

5)cos 75= cos (30+45)

There is one equation,

cos (a+b)=( cos a*cos b )+ ( sin a *sin b)

=( cos 30*cos 45)+(sin 30*sin 45)

=((√3/2)*(1/2))+((1/2)*(1/√2))

=(√3/4)+(1/2√2)

=(√3+√2)/4

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