Question

URGENT!!!
For the above question,
Since general form of quadratic equation with zeros is x^2-(a+b)x + a*b
then why can't value of k be 3?
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Answer 1

Answer:

3x^2-kx+6 = 3. 3x^2-kx+3=0.

a=3 , b=-k, c=3 so, d=b^2-4ac= k^2-36 =0, k^2=36. √k^2=√36 ,. k=6.