URGENT!!!!!
____________
Four bulbs, each of rating (100 W, 220 V) and
connected in parallel across a voltage supply of
220 V, are operated for five hours daily. If all the bulbs
are replaced by LEDs of rating (8 W, 220 V), how
many units of electrical energy will be saved every
month (30 days)?
Please help, it's urgent!!!!!!!!
Prawin11:
78.2 Kj
Its 55.2 kJh
Answers
Answered by
1
In first case,
Units of electrical energy consumed = 4 bulbs*100W*5hours*30days = 60000 WH = 60 KWH = 60 units.
In second case,
Units of electrical energy consumed= 4bulbs*8W*5hours*30days = 4800 WH = 4.8 units
Thus, Units saved = (60-4.8) = 55.2
Units of electrical energy consumed = 4 bulbs*100W*5hours*30days = 60000 WH = 60 KWH = 60 units.
In second case,
Units of electrical energy consumed= 4bulbs*8W*5hours*30days = 4800 WH = 4.8 units
Thus, Units saved = (60-4.8) = 55.2
Answered by
2
Total energy consumed by four bulbs in 30 days = 4×100×5×30 = 60000 wh
total energy consumed by LED's in 30 days=
4×8×5×30 = 4800 wh
therefore energy saved = (60000-4800) wh = 55200 wh = 55.2 kwh .
hope this will help you
if it's correct then plz list it as brainliest.
.
total energy consumed by LED's in 30 days=
4×8×5×30 = 4800 wh
therefore energy saved = (60000-4800) wh = 55200 wh = 55.2 kwh .
hope this will help you
if it's correct then plz list it as brainliest.
.
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