urgent friends class 10 board solve this question
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Solution
Width of the canal = 30 dm = 300 cm = 3 m
Depth of the canal 12 cm = 120 cm = 1.2 m
It is given that the water is flowing with velocity 10 km/hr
Therefore Length of the water column formed is
1/2 hour = 5 km = 5000 m
Therefore volume of the water flowing in 1 hour
= Volume of the cuboid of length 5000 m,
width 3 m and depth 1.2 m
=> Volume of the water in half hour
= (5000*3*1.2) m^3
= 18000 m^3
Suppose x m^2 area is irrigated in 1/2 hour
x*8/100
= 18000
x = 1800000/8
x = 225000
Hence the canal irrigated 225000 m^2 area in 1/2 hours
Solution
Width of the canal = 30 dm = 300 cm = 3 m
Depth of the canal 12 cm = 120 cm = 1.2 m
It is given that the water is flowing with velocity 10 km/hr
Therefore Length of the water column formed is
1/2 hour = 5 km = 5000 m
Therefore volume of the water flowing in 1 hour
= Volume of the cuboid of length 5000 m,
width 3 m and depth 1.2 m
=> Volume of the water in half hour
= (5000*3*1.2) m^3
= 18000 m^3
Suppose x m^2 area is irrigated in 1/2 hour
x*8/100
= 18000
x = 1800000/8
x = 225000
Hence the canal irrigated 225000 m^2 area in 1/2 hours
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