Urgent ( Geometry ) Correct answer will be followed
Attachments:
![](https://hi-static.z-dn.net/files/d3e/4403611e6c809ef29d088a83d1ee7bc6.jpg)
Answers
Answered by
1
Answer
the answer is in the figure
click above ☝☝
please mark it as brainliest
Attachments:
![](https://hi-static.z-dn.net/files/d14/fe71de304101b4b2fee9cd4e2be2a3ce.jpg)
Answered by
1
Answer:
PLZ mark as BRAINLIEST
Step-by-step explanation:
Given:
ABCD is a trapezium and AB || DC
To Prove: AO/BO = CO/DO
Construction:
Draw OE || DC such that E lies on BC.
Proof:
In triangle BDC,
By Basic Proportionality Theorem, .(1)
BO/OD= BE/EC
Now, In TRIANGLE ABC,
By Basic Proportionality Theorem,
AO/OC = BE/EC (2)
..From (1), and (2), AO/OC =BO/OD
İ.e., AO/BO= CO/DO
Attachments:
![](https://hi-static.z-dn.net/files/d20/c332ba2c4dff10d209a9973509e618da.jpg)
Similar questions