Urgent ( Geometry ) Correct answer will be followed
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the answer is in the figure
click above ☝☝
please mark it as brainliest
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PLZ mark as BRAINLIEST
Step-by-step explanation:
Given:
ABCD is a trapezium and AB || DC
To Prove: AO/BO = CO/DO
Construction:
Draw OE || DC such that E lies on BC.
Proof:
In triangle BDC,
By Basic Proportionality Theorem, .(1)
BO/OD= BE/EC
Now, In TRIANGLE ABC,
By Basic Proportionality Theorem,
AO/OC = BE/EC (2)
..From (1), and (2), AO/OC =BO/OD
İ.e., AO/BO= CO/DO
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