Question

URGENT................
GIVE REASON
NO SPAMMING

Answer 1

The Number of Electrons in N⁻³ = 10

The Number of Protons in N⁻³ = 7

The Number of Electrons in O⁻² = 10

The Number of Protons in O⁻² = 8

The Number of Electrons in F⁻¹ = 10

The Number of Protons in F⁻¹ = 9

The Number of Electrons in Na⁺ = 10

The Number of Protons in Na⁺ = 11

All these are Iso-Electronic Species, So The Ionic radius of each of these atoms depends upon the number of protons the respective atom contains. The atom which contains more number of protons has the smaller radius compared to the other Iso-Electronic species. Because, Higher positive charge pulls the electronic orbits to towards itself. In this process the Atom with more protons has a shrinked radius.

So, Na⁺ has the least radius of all of them, followed by F⁻¹, O⁻², N⁻³

So, Increasing order of ionic radii of these species is Na⁺ < F⁻¹ < O⁻² < N⁻³