Question

URGENT:

If sin-1 x + sin-1 y + sin-1 z = , then prove that

x √( 1 - x2 ) + y √( 1 -y2 ) + z √( 1 - z2 ) = 2xyz

Answer 1

sin⁻¹x + sin⁻¹y + sin⁻¹z = π
sin⁻¹x = A......x = sinA
sin⁻¹y = B......y = sinB
sin⁻¹z = C......z = sinC
A + B + C = π

x[√(1 - x²)]+ y[√(1 - y²)]+z[√(1 - z²)] = 2xyz