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And. 29 :
1)Electric field, E = 10^5 N/C
Torque, T = 8√3N-m
Dipole Moment, P = ?
We know that,
T = P x E
|T| = PE sin (60 °)
= PE √3/2
8√3= P * 10^5 *√3/2
=> P = 16 * 10^(-5) C-m
Now,
Length = 2cm = 2* 10^(-2) m
P = Q * Length
=> 16* 10^(-5) = Q * 2 * 10^(-2) m
=> Q = 8 * 10^(-3) C
Magnitude of Charge is 8 * 10^(-3) C
2)Potential Energy = -P. E
=-PE cos (60°)
= -16*10^(-5) * 10^5 cos (60°)
= -8J
1)Electric field, E = 10^5 N/C
Torque, T = 8√3N-m
Dipole Moment, P = ?
We know that,
T = P x E
|T| = PE sin (60 °)
= PE √3/2
8√3= P * 10^5 *√3/2
=> P = 16 * 10^(-5) C-m
Now,
Length = 2cm = 2* 10^(-2) m
P = Q * Length
=> 16* 10^(-5) = Q * 2 * 10^(-2) m
=> Q = 8 * 10^(-3) C
Magnitude of Charge is 8 * 10^(-3) C
2)Potential Energy = -P. E
=-PE cos (60°)
= -16*10^(-5) * 10^5 cos (60°)
= -8J
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