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Let draw BM ? PQ and CN ? RS.
Given that� PQ || RS so that� BM || CN
Use the property of Alternate interior angles
?2 = ?3 �������� � (1)
?ABC = ?1 + �?2
But ?1 =� ?2 so that
?ABC = ?2 +� ?2
?ABC = 2?2
Similarly
?BCD = ?3 +� ?4
But ?3 =� ?4 so that
? BCD = ?3 +� ?3
? BCD = 2?3
From equation first
?ABC = ?DCB
These are alternate angles so that AB || CD
Hence proved
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