Question

URGENT!!please help!! When 2 is added to the denominator and 3 is subtracted from the numerator a fraction becomes 2/9 And when 7 added to numerator and the denominator is multiplied by 3 it becomes 4/7 Find the fraction

Answer 1

Answer:

$\huge{\frac{5}{7}}$

Step-by-step explanation:

Let the original fraction be $\huge{\frac{x}{y}}$

ATQ,

$\huge{\frac{x-3}{y+2}=\frac{2}{9}}$

Cross multiplying the numerator and denominator, we get

2y+4=9x-27

2y=9x-31

$\huge{y=\frac{9x-31}{2}}$

$\huge{\frac{x+7}{3y}=\frac{5}{7}}$

Cross multiplying the numerator and denominator, we get

7x+49=12y

$\huge{\frac{7x+49}{12}=y}$

Substituting the value of y in the above equation, we get

$\huge{\frac{7x+49}{12}=\frac{9x-31}{2}}$

Cross multiplying, we get

14x+98=108x-372

-94x=-470

x=5

$\huge{y=\frac{9*5-31}{3}}$

$\huge{y=\frac{14}{2}}$

y=7

So, the answer is $\huge{\frac{5}{7}}$

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Thanks

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