URGENT
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Answer:
a.
b. y-coordinate, x-coordinate
c. 3x-5y-7=0
3(2k-1)-5(k)-7=0
6k-3-5k-7=0
k-10=0
k=10
d. Let the rectangle be OABC with the vertex O at the origin.
Let OA be the longer side.
∴ The co-ordinate of O is O(0,0).
Since one of the vertex is in the third quadrant and the longer side of length 5 units lie on the x-axis, the co-ordinate of A is A(−5,0).
Also, the rectangle lie in the III quadrant.
∴ The side OC will lie on the y-axis to the negative direction.
Then, the length of OC is 3 units.
∴ The co-ordinates of C will be C(0,−3).
Then obviously, the co-ordinates of B will be (−5,−3).
Here, OC∥AB and ∠AOC=90
o
, hence is a rectangle.
Therefore, the vertices of the rectangle are O(0,0),A(−5,0),B(−5,−3),C(0,−3).
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