URGENT PLEASE SOLVE IT
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let the speed of boat be xkm/hr
and still water be y km/hr
in case of upstream we do. b (x-y) as boat have to travel opposite direction
and (x+y) in downstream
so now according to question
3/(x-y) +4/ (x+y)=118, eq-1 {(/) means divide}
5/(x+y)+2/(x-y)=130
now let suppose 1/x-y=u and 1/x+y=v
so we can write eq-1 and 2 in following form
3u+4v=118eq-3
2u+5v=130 eq-4
now multiply eq-3 by 2 and eq-4 by 3 and then subtract eq-2 by eq-1
6u+8v=236
6u+15v=390
-7v=-154
v=22
now put value of v in eq3
3u+88=118
3u=30
u = 10
now
we have suppose 1/x-y=u
and 1/x+y= v
now put value for v and u and easily make equation in the form of x & y and simply add the equation you will get the value of x and later y...
I am not solving it because I want to boost your mind
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