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HEYA MATE, HERE IS UR ANSWER ___________________
Given - AD=BC
2)angle A =Angle B ( each 90 )
To prove - AO =BO ie CD bisects AB
Proof -In triangle AOD and Triangle BOC
AD=BC (given )
Angle A =angle B (Given )
Angle AOD=angle BOC ( VOA)
Therefore Triangle AOD congruent triangle BOC ( AAS)
Hence, AO =BO ( by CPCT)
Hence Proved
______☆☆ HOPE THE ANSWER HELPS YOU. ☆☆______☆☆BE BRAINLY ☆☆☆☆
Given - AD=BC
2)angle A =Angle B ( each 90 )
To prove - AO =BO ie CD bisects AB
Proof -In triangle AOD and Triangle BOC
AD=BC (given )
Angle A =angle B (Given )
Angle AOD=angle BOC ( VOA)
Therefore Triangle AOD congruent triangle BOC ( AAS)
Hence, AO =BO ( by CPCT)
Hence Proved
______☆☆ HOPE THE ANSWER HELPS YOU. ☆☆______☆☆BE BRAINLY ☆☆☆☆
Answered by
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In triangle AOD and triangle BOC
angle A=angle B(90°)
angleAOD=angleBOD(vertically opp.)
AD=BC
By AAS congruence rule
triangle AOD congruent triangle BOC
So,CO=DO(CPCT)
it implies AB bisects CD
angle A=angle B(90°)
angleAOD=angleBOD(vertically opp.)
AD=BC
By AAS congruence rule
triangle AOD congruent triangle BOC
So,CO=DO(CPCT)
it implies AB bisects CD
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