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A metal cuboid of dimensions 6 cm * 8 cm * 11 cm is melted and converted into a cube what is the minimum amount of metal that has to be added or removed?
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HEY .....
DIMENSIONS ARE
6CM
8CM
11CM
WE have to find its surface area ....
that is ......
=2(LB+BH+LH)
=2(6*8+8*11+6*11)
=2(202)
=404
MEANS WE HAVE TOTAL METAL AREA AS 404SQCM
NOW WE HAVE TO FIND A SURFACE AREA OF CUBE WHICH CAN BE FIT IN THIS AREA
SURFACE AREA OF CUBE
= 6*SIDE^2
IF WE ASSUME THE SIDE AS 8
THE AREA WILL BE
=6*8*8
=384
AND IF 9
THEN
=6*9*9
=486
SO THE MINIMUM FROM 404 IS 384SQCM
SO WE HAVE TO MINIMIZE THE METAL BY 404-384=20SQCM IS THE ANS.
I HOPE IT WILL HELP U....
IF YES THEN PLZ MARK AS BRAINLIEST.....☺
noe
DIMENSIONS ARE
6CM
8CM
11CM
WE have to find its surface area ....
that is ......
=2(LB+BH+LH)
=2(6*8+8*11+6*11)
=2(202)
=404
MEANS WE HAVE TOTAL METAL AREA AS 404SQCM
NOW WE HAVE TO FIND A SURFACE AREA OF CUBE WHICH CAN BE FIT IN THIS AREA
SURFACE AREA OF CUBE
= 6*SIDE^2
IF WE ASSUME THE SIDE AS 8
THE AREA WILL BE
=6*8*8
=384
AND IF 9
THEN
=6*9*9
=486
SO THE MINIMUM FROM 404 IS 384SQCM
SO WE HAVE TO MINIMIZE THE METAL BY 404-384=20SQCM IS THE ANS.
I HOPE IT WILL HELP U....
IF YES THEN PLZ MARK AS BRAINLIEST.....☺
noe
saniabiju23:
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