Question

##URGENT##
Pls answer chemistry experts!!!

balance by partial equation method :- Cu+HNO3=Cu(NO3)2+N2O+H2O

Answer 1

Given:

Cu + HNO3 ---> Cu(NO3)2 + H2O + N2O

Keep in mind: oxidation no. of Cu = +2 , NO3 = -1, 

i.e. for formation of Cu(NO3)2 we need 2 moles of HNO3

Reaction becomes, 

Cu + 2HNO3 ---> Cu(NO3)2 + 2H

However there is formation of N2O and H2O i.e we have to consider 2N and 2 O

They have to come from HNO3 we need to add 2 moles.

therefore reaction becomes,

Cu + 4HNO3 ---> Cu(NO3)2 + 2H2O + N2O + 3O 

there are 3 unaccounted O atoms, now it should be remembered that  oxygen will prefer to react with H to form H2O than form N2O

hence we need 6 H atoms, which will come from 6 HNO3, molecules

Cu + 10HNO3 ---> Cu(NO3)2 + 5H2O + N2O + 6 (NO3)-

 The unaccounted NO3- ions may be accounted by adding 1 Cu atom per 2 NO3-  ion

Now, the reaction becomes,

4Cu + 10HNO3 ---> 4Cu(NO3)2 + 5H2O + N2O

 This is the balanced reaction.

Answer 2

Answer:

4Cu + 10HNO3 → 4Cu(NO3)2 + N2O + 5H2O

Copper + Nitric Acid = Copper(II) Nitrate + Nitrous Oxide + Water