Question

urgent pls solve it fast



If the points (-1.-1).(2. p) and (8.11) are collinear, find the value of p using section
formula​

Answer 1

Step-by-step explanation:

the points are collinear so the area of triangle will be 0

ar. of ∆= 1/2[x1(y2-y3)+x2(y3-y1)+x3(y1-y2)=0

1/2[-1(p-11) +2(11+1) +8(-1-p) =0

(-p-11+22+2-8-8p) =0*2

(-9p+24-19) =0

-9p+5=0

-9p=-5

p=-5/-9

p=5/9