Question

Urgent, pls solve it!! I've been out for 1 month for holidays and I forgot everything I did earlier and I'm still trying to patch up but have less time. Pls solve it.

Answer 1

Hello Mate!

Given : OD is perpendicular from center on chord AB and BC is diameter.

To prove : AC || OD and AC = 2OD.

Proof : Since OD is perpendicular from center on chord so it must also be a line bisector By Theorum.

Hence, AD = BD. Therefore D is mid point on AB.

Similarly, OB and OC are radius.

So, OB = OC

Therefore O is midpoint on diameter BC.

Hence by mid point theorum we get that,

=> OD || AC and OD = ½ AC

=> OD || AC and AC = 2OD

Hence proved ( Q.E.D )

Have great future ahead!

Answer 2

Step-by-step explanation:

Similarly, OB and OC are radius.

So, OB = OC

Therefore O is midpoint on diameter BC.

Hence by mid point theorum we get that,

=> OD || AC and OD = ½ AC

=> OD || AC and AC = 2OD

Hence proved ( Q.E.D )

Have great future ahead!