Question

urgent plz answer fast

Answer 1

Solution

hope it helps!

Answer 2

Heya, here is your Answer :-

By Cross Multiplying L.H.S. and R.H.S.
We get :

sin^2A = (1 + cosA)(1 - cosA)

sin^2 A = 1 - cos^2A .......(Trigonometric Identity)

So,
Trigonometric Identity says ....

$\sin^{2} (A) \: = \: 1 \: - \: \cos^{2} (A)$

Therefore, LHS is equal to RHS
Hence, Solved....

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