Question

Urgent ,,, Plz solve FULL STEP

Calculate the temperature at which air possesses a density equal to that of hydrogen at 0°C . Density of air at NTP = 14.4 .
Ans:- 3658.2°c

Answer 1

The temperature at which air possesses a density equal to that of hydrogen at 0°C i.e. T2 = 3658.2°c

Given that;

The density of air at NTP= 14.4= D1

To find;

The temperature at which air possesses a density equal to that of hydrogen at 0°C i.e. T2 = ?

Solution;

We know,

Density of Hydrogen= 1 (since mass and volume are constant according to the given situation = D2

According to Charles law,

"The volume of an ideal gas is directly proportional to the absolute temperature at constant pressure".

i.e. V1/V2 = T1/T2

Then,

M/D1 / M/D2 = T1/ T2 (since d=m/v; v=m/d)

D2/D1 = T1/T2

1/14.4 = 273/ T2

T2 = 273 x 14.4

T2 = 3931.2 K

Thus, Temperature of air alone = (3931.2 - 273) K =  3658.2°c

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