Question

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Answer 1

Given

If the number of pages he read on second , third and fourth day is half the number of pages he read on previous day .

According to the given question

let he read on fourth day = x pages

Third day = 2x pages

second day = 4x pages

First day = 8x pages

Given total number of pages = 300

8x + 4x + 2x + x = 300

15 x = 300

X = 300 / 15

X = 20

so , fourth day = 20 pages

Third day 2x = 2(20) = 40 pages

second day 4x = 4(20) = 80 pages

First day = 8x = 8(20) = 160 pages.

$\bold{First \: day \: he \: read \: 160 \: pages}$

Answer 2

Let the number of pages he read on the 1st day = 'x'.

Then, the number of pages he read on second day = (x/2).

(i)

Given that on third day half the number of pages he read on previous day.

= > So, the number of pages he read on 3rd day = (x/2)/2 = x/4.

(ii)

Given on fourth day he read the number of pages he read on previous day.

= > So , the number of pages he read on 4th day = (x/4)/2 = x/8.

Now,

Given total number of pages in book = 300.

= > x + x/2 + x/4 + x/8 = 300

= > 8x + 4x + 2x + x = 2400

= > 15x = 2400

= > x = 2400/15

= > x = 160.

Therefore, the number of pages he read on first day = 160.

hope this helps!