Question

urgent question

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Answer 1

Given:

• AB || CD
• O is the midpoint of BC

To prove:

⟶ ΔAOB ≅ ΔDOC

⟶ O is the midpoint of BC

Proof:

Since AB || CD and taking AD as a transversal,

By Alternate Interior Angles,

∠OAB = ∠ODC    → → → [Equation 1]

By Vertically Opposite Angles,

∠AOB = ∠COD    → → → [Equation 2]

Now In ΔAOB and ∠COD,

• ∠OAB = ∠ODC           (From Equation 1)

• OA = OD                     (Given)

• ∠AOB = ∠COD           (From Equation 2)

By ASA congruence,

ΔAOB ≅ ΔDOC

Now by CPCT,

OB = OC

⇒ O is the midpoint of BC

★ Hence Proved ★

Answer 2

Answer:

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