Urgent question
In a triangle abc bc is equal to 12 centimetre ad equal to 15 cm ab is equal to 10 cm find the area of abc and the length of CE..
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Step-by-step explanation:
In the given figure, let CE=CF=x
It is also given that AB=12 cm, BC=8 cm and AC=10 cm, therefore,
AF=AD=10−x
BE=BD=8−x
Now consider,
AB=AD+BD
⇒12=10−x+8−x
⇒12=18−2x
⇒2x=18−12
⇒2x=6
⇒x=
2
6
=3
Therefore, CE=x=3 cm, AF=10−3=7 cm and BD=8−3=5 cm
Hence, CE=3 cm, AF=7 cm and BD=5 cm
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