Question

Urgent Question :

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Let ABC be a right triangle in which AB = 6 cm , BC = 8 cm and angle B = 90° . BD is the
perpendicular from B on AC . The circle through B , C , D is drawn . Construct the
tangents from A to this circle ?

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Accurate answer will be appreciated

Answer 1

ʜᴇʏ sɪs!!! ʜᴇʀᴇ's ᴜʀ ᴀɴsᴡᴇʀ!!! ^_^
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Construct the ΔABC  and  BD perpendicular to AC,

then draw a  circle with centre O such that BO= OC=4cm.

join the point O and A  and locate  M be the midpoint of  AO and draw a circle with centre M and radius = MO = AM.


let this circle cuts  the previous circle at   P and  Q

Now join AP and AQ  which are the desire tangents.
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ʜᴏᴘᴇ ᴛʜɪs ʜᴇʟᴘs ʏᴏᴜ ᴅɪɪ!!!! ^_^

Answer 2

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• Draw a line segment AB = 6 cm.

• Draw a right angle at B and then, BC = 8cm.

• Now,

Draw perpendicular BD to AC.

• We know in a right triangle , hypotenuse is the Diameter of circum circle.

• Considering BC as diameter ,draw a circle passing through points B, C and D.

• Join A to O and taking AO as diameter ,draw second circle.

• From point A draw tangents AB and AP.