Question

Urgent Question!!!!!!!!!!!!!!!Please solve it!!!!!!!!!!!!!!!!!!!.................
the perimeter of two squares are 40m and 96m respectively.find the perimeter of another square equal in area to the sum of the first two squares

Answer 1

perimeter of square 1 = 40 

so, its side is 40 / 4 = 10 ⇒ its area = 10 × 10 = 100

perimeter of square 2 = 96 

so, its side is 96 / 4 = 24  ⇒ its area = 24 × 24 = 576 

the third square's area is the sum of first two squares. 

so its area is 100 + 576 = 676 

⇒ its side is √676 = 26 

so, its perimeter will be 26 × 4 = 104 

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Answer 2

Heya!!

Thanks for asking the question!

Answer : 104m

Explanation :

Given,

perimeter of 2 squares i.e 40 and 96 m respectively.

Side of first square = 40/4 = 10m

Side of second square = 96/4 = 24m

Area of first square = side × side = 10×10=100m^2

Area of second square = side × side = 24 × 24 = 576m^2

The required area of new square = 100 + 576 = 676m^2

Side of this new square = square root of 676
= 26m

Perimeter of this new square = 4 × side
= 4×26 = 104m

Hope it helps you : )