Question

Urgent question plz help otherwise my teacher will beat me tomorrow ​

Answer 1

Step-by-step explanation:

here we can write it as

(log3/log2)*(log4/log3)*....(logn/logn-1)*(logn+1/logn)

so log3 will cancel,log4 will cancel and soon till logn will cancel.

we will remain with log(n+1)/log2

so we need to get answer as 10.

In log a base a is 1.

log a base b we have written as loga/logb

so in this way if we consider log 2^10/log 2 will write as log 2^10 base 2=10*log2 base 2=10

**log2 base 2 is 1

so answer is n+1=2^10 n=1024-1;n=1023

answer is 1023.