Question

urgent question The value of k for which the equations kx - y = 2 and 6x - y = 3 has a unique solution is (a) = 3 (b) not equal to 3 (c) not equal to 0 (d) = 0 pls ans fast..............

Answer 1

Answer

k ≠ 6

Given

The pair equation is :

• kx - y = 2
• 6x - y = 3

To Find

• The value of k

Solution

Given the equations are ,

kx - y = 2

6x - y = 3

$\sf Here \: \: \: a_{1}= k \: \: \: \: b_{1} = - 1 \: \: \: \: c_{1} = 2 \\ \sf and \: \: \: a_{2} = 6 \: \: \: \: \: \: b_{2} = - 1 \: \: \: \: c_{2} = 3$

Since , the pairs of equation has unique solution so we have

$\sf\longrightarrow \dfrac{a_{1}}{a_{2}} \neq \dfrac{b_{1}}{b_{2}}$

➝ k/6 ≠ -1/-1

➝ k/6 ≠ 1

➝ k ≠ 6