Biology, asked by xXIIGANGSTERIIXx, 1 month ago

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Answers

Answered by eshitabarhate12345
1

Answer:

(i) 3/root5

3(root5)/root5(root5)

=3root5/5

(ii)2/root18

2(root18)/root18(root18)

=2root18/18

(iii)2/3root7

2(3root7)/3root7(3root7)

6root7/63

(iv)1/2+root3

1(2-root3)/2+root3(2-root3)

2-root3/(2)^2-root3^2

=2-root3/4-1

=2-root3/1

(v)6/root7-root5

6(root7+root5)/root7-root5(root7+root5)

6root7+6root5/root7^2-root5^2

6root7/7-5

=6root7/2

(vi)4+root3/4-root3

4+root3(4+root3)/4-root3(4+root3)

4^2+2(4)(root3)/4^2-root3^2

8+8root3/4-3

=8+8root3/1

(vii)root3/root6

rooot3root6)/root6(root6)

=root18/6

(viii)a+b/root a+b

a+b(roota-b)/root a+b(root a-b)

a+b root a-b/root a^2-b^2

(ix)5/root8-root7

5(root8+root7)/root8-root7(root8+roor7)

5root8+5root7/root8^2-root7^2

=5root8+5root7/8-7

=5root8+5root7/1

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