[URGENT!!!] SOMEBODY HELP ME, PLEASE!
How many volume of CO2 produced for CH3COOH + NaHCO3 = CH3COONa + CO2 + H2O in ml?
Answers
Answered by
0
Answer:
1 mole of acetic acid is formed during CH3COOH+NaHCO3=CH3COONa+CO2+H2O
Answered by
1
Answer:it would be 22400ml or 22.4 litre
Explanation:as in the reaction, one mole of CH3COoH AND NAHCO3 REACTS to form 1 mole of ca2, and therefore according to stp 1 mole of co2 attains 22400ml volume.
Hope it will help you.
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