Question

URGENT!!!
The hcf and lcm of two numbers are 32 and 192 respectively. If the square of one of the numbers is a perfect cube, find the numbers.
ANSWER FAST NO SPAMMING

Answer 1

Answer:

Thus the numbers are 64 and 96

Step-by-step explanation:

LET THE NO ARE a AND b

Then ab=hcf x lcm

ab = 32 x 192

=64*96

here square of 64=64²=4096=2¹²=(2⁴)³=16³

Thus square of 64  is cube of 16

So first no a=64

now ab=32*192

64*b=32*192

b=32*192/64

=96

Thus the numbers are 64 and 96