Question

*Urgent!! Two point charges equal to -40nC and 10nC are fixed at a distance of 0.3m. Calculate the resulting intensities at the points where the electrostatic field potential is equal to 0. Determine the field potential at the point where the resulting intensity is zero.

Answer 1

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Repulsive force of magnitude 6 × 10−3 N

Charge on the first sphere, q1 = 2 × 10−7 C

Charge on the second sphere, q2 = 3 × 10−7 C

Distance between the spheres, r = 30 cm = 0.3 m

Electrostatic force between the spheres is given by the relation,

Where, ∈0 = Permittivity of free space

Hence, force between the two small charged spheres is 6 × 10−3 N. The charges are of same nature. Hence, force between them will be repulsive.

Answer 2

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Repulsive force of magnitude 6 x 10-3 N

Charge on the first sphere, q1 = 2 × 10-7C

Charge on the second sphere, q2 = 3 ×10-7 C

Distance between the spheres, r = 30 cm = 0.3 m

Electrostatic force between the spheres is given by the relation,

Where, EO = Permittivity of free space

Hence, force between the two small charged spheres is 6 x 10-3 N. The charges are of same nature. Hence, force between them will be repulsive.

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